The transition from n to o offers an exception to the trend for first ionization energy due to hund’s rules of spin pairing. if this spin pairing was not present, what would be the expected first ionization energy for the p-orbital on an oxygen atom?

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

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