Amixture contains 35.07 grams of carbon dioxide, 27.93 grams of water vapor, 12.64 grams of nitrogen, and 5.54 grams of helium. the total pressure of the system is 12 atm, what is the partial pressure of the helium?
a. 0.88 atm
b. 0.82 atm
c. 0.073 atm
d. 0.068 atm

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

1. Calculate the number of moles of each gas.

2. Calculate the total moles

3. Calculate the mole fraction of helium

4. Calculate the partial pressure of helium:

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(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied