Using the periodic table, answer the following question..how many atoms of neon are in 0.378g of neon (a) 6.02 x 10²³ atoms (b) 1.87 x 10‐²atoms (c) 2.28 x 10²³ atoms (d)1.13 x 10²² atoms.

The correct answer is D. 1.13 x 10^22 atoms are present in 0.378 g of neon. Avogadro's number (6.022 x 10^23) gives the ratio of representative particles per mole of substance. For every mole of substance, there are 6.022 x 10^23 representative particles present. Since 0.378 g of neon is less than one mole of neon, the answer should be less than Avogadro's number, which makes option D a logical answer.

Further Explanation:

To get the number of atoms present in 0.378 g of neon the following steps must be done:

STEP 1: Convert 0.378 g of Neon to moles of Neon

STEP 2: Use Avogadro's number to calculate the number of atoms of Ne

Since the given, 0.378 g has 3 significant figures, the final answer must also have 3 significant figures. Therefore,

A. 6.02 x 10^23 atoms is FALSE because the given amount of neon is less than one mole. Hence, the number of atoms cannot be equal to Avogadro's number.

B. 1.187 x 10^-2 atoms is FALSE because atoms are very very small particles. It will require a large number of atoms to make up something that is measurable like a 0.378 g sample of neon. Having less than 1 atom to make up this much sample is not logical.

C. 2.28 x 10^23 atoms is FALSE because this much atoms make up 0.3781 mol of Neon but the given is 0.378 grams not moles of Ne.

D. 1.13 x 10^22 atoms is TRUE because the value is less than 6.022 x 10^23 which is logical since the sample is less than 1 mole.

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Keywords: Avogadro's Number, Mole Conversion, Atoms

answer: i would say b.

explanation:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.