Where does oxidation and reduction take place in the reaction of br2 + 2i- → 2br + i2

Okay, let's look at the oxidation number of each substance.
-Br2 has an oxidation number of 0 because it is in a stable form.
- I- has a -1 charge and thus has an oxidation number of -1.
- 2Br- has a -1 charge also
- I2 has an oxidation number of 0 as well.

Bromine goes from 0 to -1 and Iodine goes from -1 to 0.
Therefore, Bromine is having an electron added whilst Iodine is having an electron removed.

Oxidation is Loss of electrons so Iodine is being oxidised, Reduction is Gain of electrons so Bromine is being reduced. 

The answer to the question: choose the correct statement.  a) when ethane reacts with fluorine gas the product is less stable.b) addition reactions of unsaturated hydrocarbons and halogens requires a high activation energy.  c)the double covalent bond within unsaturated hydrocarbons requires a lot of energy to break.  d)the double covalent bond within unsaturated hydrocarbons can be broken easily.is: a) when ethane reacts with fluorine gas the product is less stable.