How many joules are absorbed when 64.3 grams of water is heated from 40.0 °c to 74.0 °c?
a. 7,330 joules
b. 9,150 joules
c. 10,100 joules
d. 12,800 joules

Answer : The correct option is, (B) 9150 joules

Explanation : Given,

Initial temperature =

Final temperature =

Mass of water = 64.3 g

Specific heat of water =

Formula used :

or,

where,

Q = heat absorbed = ?

m = mass of water

= specific heat of water

= initial temperature

= final temperature

Now put all the given value in the above formula, we get:

Therefore, the heat absorbed will be, 9150 J

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products