What concentration of ni2+ ion remains in solution after electrolysis of 100. ml of 0.250 m niso4 solution when using a current of 2.40 amperes for 30.0 minutes? assume ni metal is plated out.

the concentration remains = 0.138 M

Explanation:

Let us calculate the charge passed:

The charge passed during the electrolysis = current X time(s)

charge passed = 2.40X30X60= 2160 C

we know that

96485 C = 1 F

Therefore 2160 C = 0.0224 F

according to Faraday's law of electrolysis if we pass one Faraday of charge through an electrolytic solution, 1 gram equivalent of metal will be deposited.

the gram equivalent of nickel deposited = 0.0224

The moles of Nickel deposited = 0.0224/2 = 0.0112 mol

the initial moles of Nickel ions present in solution is

The moles of nickel ion gets consumed = 0.0112

So moles of nickel ion left after electrolysis = 0.0138

the answer is either b or c

your answer would be “dry”