Astudent placed 13.0 g of glucose (c6h12o6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. the flask was then shaken until the solution was uniform. a 60.0-ml sample of this glucose solution was diluted to 0.500 l. how many grams of glucose are in 100. ml of the final solution?

There are 1.5597 grams of glucose in 100 mL of 0.08658 M glucose solution.

Explanation:

13.0 grams of glucose was added to volumetric flask and solution was made up to 100 mL.

Moles of glucose =

Volume of the solution = 100 mL = 0.1 L

Molarity of the solution =

60 mL of 0.7215 M was diluted to 0.500 L, the molarity of the solution after dilution be

(Dilution)

Mass of glucose in 0.08658 M glucose solution:

In 1 L of solution = 0.08658 moles

In 1000 mL of solution = 0.08658 moles

Then in 100 mL of solution :

of glucose

Mass of 0.008658 moles of glucose:

There are 1.5597 grams of glucose in 100 mL of 0.08658 M glucose solution.

m_{C_6H_{12}O_6}=1.56g

Explanation:

Hello,

After the dilution, the concentration of glucose is:

Now, we apply the dilution equation to compute the concentration after the dilution to 0.500L (500mL):

Finally, we compute the present grams in 100mL of the 0.0156g/mL glucose solution as shown below:

Best regards.

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the nucleus together due to an excess of either protons or neutrons.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.