Assume you add 5 g of nacl to a beaker and add water until the volume of the solution reaches 4 l. calculate the concentration of salt in water in g/l and mol/l.

1.25 g/L.

0.0214 mol/L.

Explanation:

Concentration in g/L = 5/4

= 1.25 g/L (answer).

As for  mol / L we need to know the molar mass of salt.

It is 22.99 + 35.45 = 58.44.

So in mol/L it is  1.25 / 58.44

= 0.0214 mol/L.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%