Describe how you would prepare 500.0ml of an aqueous solution that is 30.0% isopropyl alcohol by volume

The solution can be prepared by adding 150.0 mL of isopropyl alcohol to 350.0 mL of water to make 30.0% isopropyl alcohol aqueous solution.

Explanation:

∵ The volume% of a solution = [(volume of the solute(isopropy)/(volume of the solution)] x 100.

The volume % = 30.0%, volume of the solution = 500.0 mL.

∴ Volume of the solute = (the volume% of a solution)(volume of the solution)/100 = (30.0%)(500.0 mL)/100 = 150.0 mL.

∵ The volume of solution = volume of the solute + volume of water

∴ Volume of water = volume of the solution - volume of the solute = (500.0 mL) - (350.0 mL) = 150.0 mL.

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