Given the following equation: 2 c4h10 13 o2 > 8 co2 10 h20 + how many grams of co2 are produced if 12.4 grams of c4h10 reacts with 56.9 grams of o2?

Answer : The mass of produced will be, 37.488 grams.

Explanation : Given,

Mass of = 12.4 g

Mass of = 56.9 g

Molar mass of = 58 g/mole

Molar mass of = 32 g/mole

Molar mass of = 44 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 13 mole of

So, 0.213 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of .

As, 2 moles of react to give 8 moles of

So, 0.213 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the mass of produced will be, 37.488 grams.

b) mutualism

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increased stability in the completion of fluorine's outer shell.