The mond process produces pure nickel metal via the thermal decomposition of nickel tetracarbonyl: ni(co)4 (l) → ni (s) + 4co (g). what volume (l) of co is formed from the complete decomposition of 444 g of ni(co)4 at 752 torr and 22.0 °c?

The volume of CO formed is 254.43 L.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of = 444 g

Molar mass of = 170.73 g/mol

Putting values in above equation, we get:

For the given chemical reaction:

By stoichiometry of the reaction:

1 mole of nickel tetracarbonyl produces 4 moles of carbon monoxide.

So, 2.60 moles of nickel tetracarbonyl will produce = of carbon monoxide.

Now, to calculate the volume of the gas, we use ideal gas equation, which is:

PV = nRT

where,

P = Pressure of the gas = 752 torr

V = Volume of the gas = ? L

n = Number of moles of gas = 10.4 mol

R = Gas constant =

T = Temperature of the gas =

Putting values in above equation, we get:

Hence, the volume of CO formed is 254.43 L.

po-215 i got it right on the quiz

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o