Acompound is 54.53% c,54.53% c, 9.15% h,9.15% h, and 36.32% o36.32% o by mass. what is its empirical formula? insert subscripts as needed. empirical formula: chocho the molecular mass of the compound is 132 amu.132 amu. what is its molecular formula? insert subscripts as needed. molecular formula: cho

Answer : The molecular of the compound is,

Solution : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 54.53 g

Mass of H = 9.15 g

Mass of O = 36.32 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

For O =

The ratio of C : H : O = 4 : 8 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula =

The empirical formula weight = 12(4) + 8(1) + 1(16) = 72 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

Molecular formula =

Therefore, the molecular of the compound is,

i'm pretty sure it is letter c.) car

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.