The molarity of a vinegar solution is 0.90m. calculate the nimber of acetic acis moles is 10 ml of the solution

0.009 mol.

Explanation:

Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of acetic acid)/(Volume of the solution (L)).

M = 0.9 M, Volume of the solution = 10.0 mL = 0.01 L.

∴ no. of moles of acetic acid = (M)(Volume of the solution (L)) = (0.9 M)(0.01 L) = 0.009 mol.

They can measure  the amount of energy gained or lost

☆ionisation energy increases across a period from na -> ar☆ionisation energy decreases down a group from li -> fr☆ionic radius decreases across a period from na -> cl☆ionic radius increases down a groupfrom f -> ii hope it clarifies your doubts