In each of the following blanks, only enter a numerical value. 1) in a sublevel for which l = 0, there are orbital(s), and the maximum number of electrons that can be accommodated is 2) in a principle energy level for which n = 3, the maximum number of electrons that can be accommodated is 3) give the appropriate values of n and l for an orbital of 3p: n = and l =

Explanation:

1) In a sublevel for which l = 0, there are _1__ orbital(s), and the maximum number of electrons that can be accommodated is _2__.

l represents the azimuthal quantum numbers and l = n-1. Where n is the principal quantum number. The principal quantum number(n) gives the main energy level in which the orbital is located.

For l = 0, n = 1

To find the maximum number of electrons, we use 2n². Where n is 1 for the given problem.

2) In a principle energy level for which n = 3, the maximum number of electrons that can be accommodated is _18__.

We simply evaluate using 2n², since n = 3, the maxium number of electrons would be 2(3)² = 18 electrons

3) Give the appropriate values of n and l for an orbital of 3p: n = _3__, and l = _1__.

3p denotes the principal quantum number(n) and the azimuthal quantum number(l)

n = 3

l = 1

An atom with principal quantum number of 3 will have azimuthal numbers of 0,1 and 2. This shows that six electrons can fill the three degenerate orbitals.

The orbital designation is given as:

                 for 0                        3s

                       1                         3p

                       2                         3d

This is why the 3p orbital will have an azimuthal number of 1.

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