How much heat is released when 15.0 g of water vapor is condensed and then cooled from 100.0 c to -32.0 c? show work ❤️

46148 J

Explanation:

You need to calculate the heat associated with each of the following steps. You will need to know some specific heats (they are probably given to you somewhere).

Step #1: Condensation

Step #2: Cooling from 100 C to 0 C

Step #3: Freezing

Step #4: Cooling from 0 C to -32 C

Step #1:

q = mC

q = 15 g (-2256 J/g )

q = -33840 J

Step #2:

q = mcΔT

q = 15 g (4.19 J/g/C)(-100 C)

q = 6285

Step #3:

q = mC

q = 15 g (-334 J/g)

q = -5010

Step #4:

q = mcΔT

q = 15 g (2.11 J/g/C)(-32 C)

q = -1013

Keep in mind the - signs indicate heat is being released. To calculate the total heat released, add the individual heats calcualted at each step:

Total heat released = 33840 + 6285 + 5010 + 1013 = 46148 J

43.452

step-by-step explanation:

284 times .153 = 43.452

b.

the accuracy of the data.