How much energy is required to vaporize 10 grams of water at its boiling point? in joules.

The energy required to vaporize the given amount of water is 22600 J

Explanation:

The conversion involved in this process are:

To calculate the amount of heat required at constant temperature, we use the equation:

where,

= amount of heat absorbed = ?

m = mass of water = 10 g

= latent heat of vaporization = 2260 J/g

Putting all the values in above equation, we get:

Hence, the energy required to vaporize the given amount of water is 22600 J

if you mean hydrogen and oxygen then water is the product