What is the total number of moles present in a 526.0-gram sample of nanco3(s)?

5.42 mol

Explanation:

To find moles, divide the given mass by the compounds molar mass. To find the molar mass of the compound, add of the masses of each individual component:

Molar mass of NaNCO3 = Na + N + C + (O x 3)

Molar mass of NaNCO3 = 23 + 14 + 12 + (16 x 3)

Molar mass of NaNCO3 = 97 g/mol

Moles = mass / molar mass

Moles = 526 g / 97 g/mol

Moles = 5.42 mol

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).