Percent iron in a mixture that is 52.2% fe2o3

36.51%.

Explanation:

First find the percentage of iron in pure Fe2O3 using the  atomic masses of the elements:

=  (2 * 55.845) * 100 /  (2*55.845+ 3*15.999)

=  69.94 %.

So the percentage of iron in the mixture

=  52.2 * 0.6994

= 36.51 (answer).

is it a purebred? it looks more like a red nose, but it doesn't have the red could it be a staffordshire bull terrior? unsure if that's the right name for it sorry

2b2t

explanation:

2b2t