Astudent increases the temperature of a 417 cm3 balloon from 65°c to 126°c. what will the new volume of the balloon be?

492.3 cm³.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(V₁T₂) = (V₂T₁).

V₁ = 417.0 cm³, T₁ = 65°C + 273 = 338 K.

V₂ = ??? cm³, T₂ = 126°C + 273 = 399 K.

∴ V₂ = (V₁T₂)/(T₁) = (417.0 cm³)(399 K)/(338 K) = 492.3 cm³.

if you mean hydrogen and oxygen then water is the product