If a gas occupies at 5.40 l at a pressure of 1.25atm, what will be its volume at a pressure of 3.00 atm? (show work)

Explanation:

Givens

P = 1.25 atm

V = 5.4 L

P1 = 3 atm

V1 = ??

Formula

The basic formula is P*V = P1 * V1

Solution

1.25 * 5.4 = 3 * V1

6.75 = 3*V1

6.75 /3 = 3*V1/3

2.25 = V1

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

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enthalpy change for the reaction between the given volumes of the gases is :

the dissolution of polymer can be thermodynamically described in 2 steps.