The volume of a gas at 27.0c and 0.200atm is 80.0 ml .what volume will the same gas sample occupy at stp?

V₂ = 14.56 mL.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(P₁*V₁) / T₁ = (P₂ * V₂) / T₂

V₁  =  80.0 mL, P₁ = 0.20 atm, T₁ = 27  °C + 273 = 300 K.

V₂  =  ??? mL, P₂ (STP) = 1.0 atm, T₂ (STP) = 0 °C + 273  =  273 K.

Applying in the above equation

(P ₁* V₁) / T₁ = (P₂ * V₂) / T₂

(0.20 atm * 80.0 mL) / 300 K= (1.0 atm  * V₂) / 273 K

V₂ = (0.20 atm * 80.0 mL * 273 K) / (300 K * 1.0 atm)

V₂ = 14.56 mL

So, the answer is: V₂ = 14.56 mL.

what are the two models

explanation:

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