Chemistry, 22.09.2019 00:50 daeshawnc14

Given the following heats of combustion: c2h2(g) = -1300 kj/mole, h2(g) = -286 kj/mole, c2h6(g) = -1560 kj/mole, calculate the enthalpy change for the following reaction
c2h2(g) + 2h2(g) → c2h6(g)
a. -312 kj
b. -26 kj
c. +312 kj
d. -26 kj

Answers: 1

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Given the following heats of combustion: c2h2(g) = -1300 kj/mole, h2(g) = -286 kj/mole, c2h6(g) = -...

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Given the following heats of combustion: c2h2(g) = -1300 kj/mole, h2(g) = -286 kj/mole, c2h6(g) = -1560 kj/mole, calculate the enthalpy change for the following reaction c2h2(g) + 2h2(g) → c2h6(g) a. -312 kj b. -26 kj c. +312 kj d. -26 kj

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Another question on Chemistry

Given the following heats of combustion: c2h2(g) = -1300 kj/mole, h2(g) = -286 kj/mole, c2h6(g) = -1560 kj/mole, calculate the enthalpy change for the following reaction
c2h2(g) + 2h2(g) → c2h6(g)
a. -312 kj
b. -26 kj
c. +312 kj
d. -26 kj