If a 53.27g sample of potassium nitrate (kno3) is dissolved in enough water to make 461 ml of solution, what will be the molarity?

1.143 M.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of KNO₃/(V of the solution (L)).

∴ M = (mass/molar mass)of KNO₃/(V of the solution (L)) = (53.27 g / 101.1 g/mol)/(0.461 L) = 1.143 M.

the answers would be

the first one and the second one

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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