Agas with a volume of 4.0 is allowed to expand to a volume of 12l. what happened to the pressure in the container if the temperature remains constant

We use old  

Boyle's Law

,  

P

V

=

k

,

where  

k

is a  

constan

And the utility of this law means that we could use non-standard units, if our units are consistent.

Given that  

P

V

=

k

,

(temperature constant), it follows that

P

1

V

1

=

P

2

V

2

We solve for  

P

2

=

P

1

V

1

V

2

=

205

⋅

k

P

a

×

4.0

⋅

L

12.0

⋅

L

≅

68

⋅

k

P

a

Explanation:

it should be p1 v1 = p2 v2