Ba(oh)2 = ba2 + 2oh- (dissolved in solution). which will not happen to the equilibrium of this solution as h+ ions are added?

h+ will combine with oh- to form water

the base will dissociate to form more oh-

the reaction will move to the right

the reaction will move to the left

the quantity of ba(oh)2 will decrease

The reaction will move to the left.

Explanation:

Ba(OH)₂ = Ba²⁺ + 2OH⁻,

Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.

H⁺ will combine with OH⁻ to form water.

So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.

According to Le Châtelier's principle: when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

The base will dissociate to form more OH⁻ and thus, the quantity of Ba(OH)₂ will decrease.

So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.

answer: i would say b.

explanation: