Agas occupies 49 liters at a pressure of 367 mm hg. what is the volume when the pressure is increased to 784 mm hg?

22.94 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have two different values of V and P:

P₁V₁ = P₂V₂

P₁ = 367.0 mm Hg, V₁ = 49.0 L.

P₂ = 784.0 mm Hg, V₂ = ??? L.

∴ V₂ = P₁V₁/P₂ = (367.0 mm Hg)(49.0 L)/(784.0 mm Hg) = 22.94 L.

the dependant variable is spilled water

the independent is the heat