Zn + 2 hcl --> zncl2 + h2 how many moles of hydrochloric acid (hcl) are used (assume a complete reaction) if 8.3 moles of zinc chloride (zncl) are produced? a 8.3 mol zncl2 b none of these answers c 8.3 mol hcl d 4.15 mol hcl e 16.6 mol hcl

E. 16.6 mol HCl

Explanation:

The equation for the reaction is;

Zn + 2 HCl --> ZnCl2 + H2

From the reaction 2 moles of HCl produces 1 mole of ZnCl2

Therefore; 8.3 moles of ZnCl2 will be produced by;

  = 8.3 moles ×2

  = 16.6 Moles of HCl

  Therefore;  E.  16.6 mol HCl

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