What is the reducing agent in the following reaction? ( respond fast)
2na + s --> na2s
a. na
b. s
c. na2s
d. na+

A) Na

Explanation:

We analyze the change of electrons in the equation.

So:

S (0) --> S (-2)

The oxidizing agent is the one that gains electrons. Sulfur goes from 0 to -2 then it is gaining electrons.

Na (0) --> Na (+1)

The reducing agent is the one that loses electrons. Sodium goes from 0 to +1 which means that it loses electrons.

Therefore the reducing agent is Na.

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