What will be the cell potential for a cu−zn galvanic cell with [zn2+]=0.1 m and the [cu2+]=0.01 m? view available hint(s)?

1.07 V

Explanation:

The metal with negative reduction potential will easily lose electrons and thus is oxidized and the one with positive reduction potential will easily gain electrons and thus is reduced.

= standard electrode potential =

Using Nernst equation:

where,

n = number of electrons in oxidation-reduction reaction = 2

3 hours because it is a decent distance.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer