How many moles of sucrose (c12h22o11) would be in 8.7 l of a 1.1 m solution of sucrose?

9.57 mol.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.