The ka of acetic acid (hc2h3o2) is 1.8 ⋅ 10-5. what is the ph at 25.0 °c of an aqueous solution that is 0.100 m in acetic acid? the ka of acetic acid (hc2h3o2) is 1.8 10-5. what is the ph at 25.0 °c of an aqueous solution that is 0.100 m in acetic acid? +2.87 -2.87 -11.13 +6.61 +11.13

2.872.

Explanation:

∴ [H⁺] = √(Ka.C) = √(1.8 x 10⁻⁵)(0.1 M) = 1.342 x 10⁻³.

∵ pH = - log[H⁺].

∴ pH = - log(1.342 x 10⁻³) = 2.872.

for points guys

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.