At a certain temperature, a mixture of 2 gases, 11.2 g of oxygen and 104.75 of krypton exert a total pressure of 4.25 atm. what is the partial pressure of each gas in mm hg?

Pressure of O₂ = 0.93 atm

Pressure of krypton = 3.32 atm

Explanation:

This problem can be solved by using Dalton's Law of Partial Pressures, which states that the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture.

Pₐ = Xₐ * Ptotal

P ₐ  - the partial pressure of component  a  

χ ₐ   - its mole fraction in the mixture

P total  - the total pressure of the mixture

The moles of the two gases are:

moles of O₂ = 11.2/32 = 0.35 moles

moles of krypton = 104.75/83.8 = 1.25 moles

Total moles = 1.25 + 0.35 = 1.6 moles

Xₐ = number of moles of a /total moles in mixture

Pressure of O₂ = 0.35/1.6 *4.25 = 0.93 moles

Pressure of krypton = 1.25/1.6 *4.25 = 3.32 moles

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

answer carbon and three oxygen atoms;