Dwayne filled a small balloon with air at 298.5 k. he put the balloon into a bucket of water, and the water level in the bucket increased by 0.54 liter.
if dwayne puts the balloon into a bucket of ice water at 273.15 k and waits for the air inside the balloon to come to the same temperature, what will the volume of the balloon be? assume the pressure inside the balloon doesn’t change.

Explanation:

Dwayne filled a small balloon with air at 298.5 K. He put the balloon into a bucket of water, and the water level in the bucket increased by 0.54 liter.

If Dwayne puts the balloon into a bucket of ice water at 273.15 K and waits for the air inside the balloon to come to the same temperature, what will the volume of the balloon be? Assume the pressure inside the balloon doesn’t change.

Type the correct answer in the box. Express your answer to the correct number of significant figures.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.