How many grams of nh3 can be produced from the reaction of 28 g of n2 and 25 g of h2

Explanation:

1) Balanced chemical equation

2) Stoichiometric (theoretical ) mole ratios

3) Number of moles of each reactant

4) Limiting reactant

Since the stoichiometry states that 1 mol of N₂ reacts with 3 moles of H₂, the given mass of N₂ will react completely with the given amount of H₂, and the calculations must be done with the 28 g (1 mol) of N₂ as the limiting reactant.

5) Yield

Set the proportion with the mole ratios:

1 mol H₂ / 2 mol NH₃ = 1  mol H₂ / x ⇒ x = 2 mol NH₃

6) Convert to grams

the reaction of 28 g of N₂ with 25 g of H₂ will produce 34 g of NH₃

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