A31.5 ml aliquot of h2so4 of unknown concentration was titrated with 0.0134 m naoh. it took 23.9 ml of the vase to reach the endpoint of the titration. what was the concentration of the acid

solve for the molarity of H+, which reacts 1:1 withNaOH, using:

M1V1 = M2V2

(M1)(31.5 ml) = (0.0134M)(23,9ml)

M1 = 0.010167 molar H+ ion

since it takes 2 H+ ions to make 1 H2SO4:

0.010167 molar H+ ion => 1/2 as much=> 0.00508 M H2SO4

your answer is 0.00508 M H2SO4

c. is the answer

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