I’m not sure how to do this. sorry for cutting off the question at first.

Both those acids are strong acids, so it's a titration with a strong acid and a strong base, creating a neutralization reaction.

a) The pH before any NaOH has been added would just be the -log[HCL]. -log[.1] is equal to 1.

b) First, figure out how many mmol of HCl you have. x/25=.1 would be 2.5 mmol of HCl. There's x/10=.1 of NaOH, so you have 1 mmol of NaOH. 1 mmol of the HCl reacts away, so you have 1.5 mmol of HCl in 35 mL. 1.5/35 = .042 M. -log(.042) = 1.38.

c) In a titration with a strong acid and a strong base, the pH at the equivalence point is always equal to 7.

d) Now you have 10 mL beyond the equivalence point. We need to figure out how much was added to get to the equivalence point so we can calculate the concentration of NaOH to find the pOH and then pH. Well, since they have equal concentrations, it would be 25 mL of NaOH, plus the 10 we just added. So we have 35 mL + 25 mL of the HCl, which is 60 mL total. If we had 35 mL of NaOH originally, that would be 3.5 mmol of NaOH (x/35=.1). 3.5/60 is .0583. -log.0583  is 1.23. pH = 14 - pOH. 14 - 1.23 = 12.77

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .