A1.225 g sample mixture of lithium hydrogen carbonate is decomposed by heating to produce 0.660 g lithium carbonate. calculate the theoretical yield and percent yield of li2co3

Explanation:

2LiHCO₃(s) → Li₂CO₃(s) + H₂CO₃(g).

It is clear that 2.0 moles of lithium hydrogen carbonate produce 1.0 mole of lithium carbonate.

no. of moles of lithium hydrogen carbonate = mass/molar mass = (1.225 g)/(67.96 g/mol) = 0.018 mol.

∴ The theoretical yield of lithium carbonate = no. of moles x molar mass = (0.009 mol)(73.89 g/mol) = 0.6659 g.

∵ The percent yield = (actual yield/theoretical yield) x 100 = (0.660 g / 0.6659 g) x 100 = 99.11%.

i think that the answer is c