2li +__h₂0= __lioh+h₂
balance the equation

2Li+2H2O=2LiOH+H2

We need to make number of the atoms of each reactant(the elements from the left side)equaled to the products(the elements from the right side)

Li is 2 on the left side so in order to make it balanced we add a 2 in front of LiOH.

For the H2O we take a look at the right side there are 2 atoms from H2 and 2 atoms of H for 2LiOH therefore we have 4 atoms of H in the right side and only 2 in the left side.So,to make them equal we will add a 2 in front of H2O.

Hope,I explained well.

it should be all of them because it asks if you included all of those in your answer

explanation:

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.