Calculate the approximate volume of a 1.50 mol sample of gas at 15.0oc and a pressure of 3.75 atm.

The approximate value of the volume of the gas is 958.3L

Using the ideal gas equation which is a combination of pressure law, Boyle's law and Charles's law.

Mathematically

we convert the value of temperature from degree Celsius to Kelvin.

To do this, simply add 273.15 to the °C value.

From the data given, we can substitute into the equation and solve for v

The approximate value of the volume is 958.3L

Learn more on ideal gas equation here;

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V = 6.30L

PV = nRT

15°C = 15+273 = 288K

3.75*V = 1.50*0.082057*288

V = (1.50*0.082057*288)/3.75

V = 6.30L

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)