What is the molarity of 3 moles of nacl in 12 liters of water

Molarity=Moles of solute

Volume of SOLUTION

And we get an answer with units, mol⋅L−1

Explanation:

So all we need to do is to set up this quotient. You have been given the amount of solute in moles, and the volume of solution.

So, Molarity=3⋅mol

4⋅L. =??mPol⋅L−1?In 1L of this solution, what is the mass of the NaCl solute?

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%