Remember to explain and show work.

26. how much heat will be absorbed if 45.0 g of c react with excess water?

27. how much heat is released when 9.22 grams of glucose c6h12o6 in your body reacts with according to the following equation?

26. 42.3 kJ; 27. 143 kJ  

Explanation:

26. Formation of water gas

We know that we will need the balanced equation with masses, molar masses, and enthalpies, so let’s gather all the information in one place.

A_r:        12.01

                 C + H₂O ⟶ CO + H₂; ΔH_r = +113 kJ

Mass/g:  4.50

(a) Calculate the moles of C

Moles of C = 4.50 × 1/12.01 = 0.375 mol C

(b) Calculate the energy absorbed

The conversion factor is 113 kJ/1 mol Al

Heat = 0.375 × 113/1 = 42.3 kJ

27. Oxidation of glucose

A_r:         180.16

               C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O; ΔH_r =  -2803 kJ

Mass/g:     9.22

(a) Calculate the moles of C₆H₁₂O₆

Moles of C₆H₁₂O₆ = 9.22 × 1/180.16 = 0.051 07 mol C₆H₁₂O₆

(b) Calculate the energy absorbed

The conversion factor is (-2803 kJ/1 mol C₆H₁₂O₆)

Heat = 0.051 07 × (-2803)/1 = -143 kJ

The oxidation of glucose releases 143 kJ .

the answer to your question is c.

if you read the house of usher you should know that the house was haunted

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.