Apropane tank containing 55l has 2.46 moles of the gas c3 is propane what would the number of moles if 1/2 of the gas is used

= 1.23 moles

V1/n1 = V2/n2

V1 = 55 L, n1 =2.46 moles

1/2 of the gas was used and thus; 1/2 or 27.5 L remained.

Therefore;

55 L/2.46 moles = 27.5 L/ n2

n2 = (2.46 × 27.5)/55

    = 1.23 moles