When mercury (ii) oxide is heated it decomposes into mercury and oxygen gas how many molecules of oxygen gas are produced if 23.0g of mercury (ii) oxide are heated

= 3.1966 × 10^22 molecules of Oxygen

The equation for the reaction is;

2 HgO → 2 Hg + O2

Given 23 g of HgO ;

Moles of HgO = 23 / 216.6 g/mol

                       = 0.1062 moles

Mole ratio; HgO : O2 = 2 : 1

Thus; moles of Oxygen = 0.1062 moles/2

                                       = 0.0531 moles

But; 1 mole of oxygen = 6.02 × 10 ^23 molecules

Therefore; molecules of oxygen produced

= 6.02 × 10^23 molecules × 0.0531 moles

= 3.1966 × 10^22 molecules

the answer is a. co2, this would be colder than the : )

explanation:

the dependant variable is spilled water

the independent is the heat