If this atom were to lose its outer shell electron the ten remaining electrons would

a. remain in their shells.

b. form an ionic bond with another atom.

c. shift so that one electron would move up to take the place of the lost electron.

d. attract an electron from another atom in order to form an ionic bond with that atom.

Okay so basically there can only be 8 electrons on an outer shell.

If there were 10 remaining then it would be 2 on the first shell and 8 on the second. The second shell will be full.

So basically nothing would happen (A)

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."