Apotassium hydroxide (koh) solution has a molar concentration of 0.065 m, calculate the [h3o+], [oh-] and ph of the solution.

1) [OH⁻] = 0.065 M

2) [H₃O⁺] = 1.54 x 10⁻¹³ M.

3)  pH = 12.81.

Explanation:

HCl is completely dissociated yo its ions in solution:

KOH + H₂O  → H₃O⁺ + K⁺ + OH⁻,

1) [OH⁻] = 0.065 M.

2) [H₃O⁺]:

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(0.065 M) = 1.54 x 10⁻¹³ M.

3) pH:

For strong acids like HCl:

pH = - log[H₃O⁺] = - log[1.54 x 10⁻¹³ M] = 12.81.

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