In an ion, the sum of the oxidation states is equal to the overall ionic charge. note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. in oh−, for example, the oxygen atom has an oxidation state of −2 and the hydrogen atom has an oxidation state of +1, for a total of (−2)+(+1)=−1. what is the oxidation state of an individual sulfur atom in so32− ?

the oxidation state of an individual sulfur atom in SO₃⁻² is +4.

Explanation:

1) Fundamental considerations: There are important rules that you need to know to find the oxidation states of neutral compounds or ions.

Those are the relevant rules for this question.

2) Procedure:

4) Conclusion: the oxidation state of an individual sulfur atom in SO₃⁻² is +4.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

im pretty sure its b