A50.0-ml volume of 0.15 m hbr is titrated with 0.25 m koh. calculate the ph after the addition of 16.0 ml of koh.

moles HBr = 0.0500 L x 0.15 M=0.0075 

moles KOH = 0.0160 L x 0.25 M=0.0040 

moles H+ in excess = 0.0075 - 0.0040= 0.0035 

total volume = 0.070 L 

[H+]= 0.0035/0.070=0.050 M 

pH =1.55

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

catya that's not even a b or c