What is the density of a gas with a molar mass of 28.26 grams per mole at 3.510 atm in 237 kelvin

= 5.1 g/L

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Number of moles is 1 since one mole has a mass equivalent to the molar mass.

Therefore; We can find the volume and thus get the density.

V = nRT/P

   = (1 × 0.08206 × 237)/3.510

    = 5.5408 L

Hence; Density = mass/volume

                          = 28.26 g/5.5408 L

                          = 5.1 g/L

The Density is 5.1 g/L or 0.005 g/cm³

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.