Asample of gas occupies a volume of 120.0 ml at a pressure of 0.75 atm and a temperature of 22°c
what will the volume be at a pressure of 1.25 atm and a temperature of 70.0°c?

The is as follows
P1 V1 \ T1=P2 V2/T2
where, p1=0.75, v1=120.0, T1=22, p2=1.25,
V2=?, T2=70.0
:: 0.75 x 120.0/ 22 = 1.25 x v2/ 70.0
90/22=1.25v2/70.0
(cross multiply ).
1.25v2 x 22=90 x 70.0
27.5v2=6300
(divide by the coefficient of the unknown = v2).
27.5v2/27.5=6300/27.5
V2=229.090; =229.1
:: The volume will be at 229.090 or 229.1.