Part 1. a chemist reacted 18.0 liters of f2 gas with nacl in the laboratory to form cl2 gas and naf. use the ideal gas law equation to determine the mass of nacl that reacted with f2 at 290. k and 1.5 atm.

f2 + 2nacl → cl2 + 2naf

part 2. explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at stp.

Part 1.

Balanced chemical reaction:

F₂ + 2NaCl → Cl₂ + 2NaF

To determine the mass of NaCl that reacted with F₂ we must first determine the moles of F₂ associated with 18.0 L of this gas at 290 K and 1.5 atm, for which we will use the law of ideal gases.

According to the law of ideal gases:  

PV = nRT  → n = PV / RT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the gas constant (0.082057 atm L / mol K) .

If P = 1.5 atm, V = 18.0 L and T = 290 K:

→

Then, the mass of NaCl that react with 1.13 mol of F₂ according to the stequiometric coefficients in the balanced chemical reaction will be:

So, the mass of NaCl that reacted with 18.0 liters of F₂ at 290. K and 1.5 atm is 132 g of NaCl

Part 2.

According to IUPAC, STP (Standard conditions for Temperature and Pressure) is defined as a temperature of 273.15 K and an absolute pressure of exactly 1 bar which is equal to 0.986923 atm ≈ 1 atm.

To determine the mass of NaCl that react with 18.0 L of F₂ gas at STP you can use the law of ideal gases to determine the moles of F₂ that 18.0 L of this gas contain at 273.15 K and 1 atm. Then, you can calculate the mass of NaCl that react with those moles of F₂ according to the stequiometric coefficients in the balanced chemical reaction, as you did before.

Then,

→

So, the mass of NaCl that reacted with 18.0 liters of F₂ at STP (273.15 K and 1 atm) is 94 g of NaCl.